What is the derivative f(x)=0?
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http://www.wolframalpha.com/input/?i...e+f%28x%29%3D0
very useful website (I work there). Use it to check any of your calculus answers!
very useful website (I work there). Use it to check any of your calculus answers!
Thanks!
Who's your math teacher? I just graduated from there in '09.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
.Being in econ classes right now makes me want to take math again..
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Found this on mathlab
(1) Write the complex function in the form f(z) = a(x,y) + i
b(x,y), with z = x + i y
(2) f(z)=0 only if a(x,y) = 0 and b(x,y) = 0 both hold
simultaneously
(3) Plot the (possibly implicit) relations a(x,y)=0 and b(x,y)=0
in the x-y plane and visually inspect the graphs for crossings of these two
curves. This should give you a good idea of starting values for FZERO
b(x,y), with z = x + i y
(2) f(z)=0 only if a(x,y) = 0 and b(x,y) = 0 both hold
simultaneously
(3) Plot the (possibly implicit) relations a(x,y)=0 and b(x,y)=0
in the x-y plane and visually inspect the graphs for crossings of these two
curves. This should give you a good idea of starting values for FZERO
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Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
You are learning the basics now, and it seems really formulaic, but as you learn more, you'll start to realize just how much of this is used in pretty much all technology... including cars. You're starting with derivatives now, but the reverse of that is integrals; and that's where it gets (wierd initially then) really interesting.
Calculus would be used for analyzing the fastest way through a course by integrating the optimal midcorner speeds, or explaining the powerband of an engine, heck the turbo flow chart demonstrates it.
Good luck. Don't blow off calculus.
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For the OP... just some advice... you need to understand the description above because calculus is not a rote memory subject. You will not be able to memorize how to do things and do well in the course. You might be able to be "good at homework", but even then you are robbing yourself of understanding some pretty pervasive advanced mathematics.
You are learning the basics now, and it seems really formulaic, but as you learn more, you'll start to realize just how much of this is used in pretty much all technology... including cars. You're starting with derivatives now, but the reverse of that is integrals; and that's where it gets (wierd initially then) really interesting.
Calculus would be used for analyzing the fastest way through a course by integrating the optimal midcorner speeds, or explaining the powerband of an engine, heck the turbo flow chart demonstrates it.
Good luck. Don't blow off calculus.
You are learning the basics now, and it seems really formulaic, but as you learn more, you'll start to realize just how much of this is used in pretty much all technology... including cars. You're starting with derivatives now, but the reverse of that is integrals; and that's where it gets (wierd initially then) really interesting.
Calculus would be used for analyzing the fastest way through a course by integrating the optimal midcorner speeds, or explaining the powerband of an engine, heck the turbo flow chart demonstrates it.
Good luck. Don't blow off calculus.
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Thanks everyone. Thats what I thought... then I thought that it may have been a trick questions. Being a Business Calc class, our teacher knows that this is probably going to be all of our last calc classes. ever. Conceptually, I knew that a constant would be zero but I wasn't sure if there was a special rule for zero. I guess there isn't, so I guess I got it right. haha
