What is the derivative f(x)=0?
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woooow yeah, they would pull that on you at pomona. even in the business calc class. tsk tsk. To ask that question on a test requires a science related course and build up lectures. It makes much more sense to think about it in a purely mathematical or scientific sense. Since it's biz calc, all the problems are probably applied, in which case this test is just all about who read AND memorized every single passage and caveat in the book. Stupid way to learn, no?
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woooow yeah, they would pull that on you at pomona. even in the business calc class. tsk tsk. To ask that question on a test requires a science related course and build up lectures. It makes much more sense to think about it in a purely mathematical or scientific sense. Since it's biz calc, all the problems are probably applied, in which case this test is just all about who read AND memorized every single passage and caveat in the book. Stupid way to learn, no?
He probably told us during lecture as a side note.
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I don't doubt it. Their math dept is world reknown. I think it's stupid that biz calc classes are forced to "weed" out the lazies by resorting to such tricks. It's a cheap shot.
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This is pretty entertaining... But a little sad too.
It doesn't really weed out the lazies, just people who don't learn well that way or didn't get it for whatever reason. Everyone's different and some instructors don't seem to get that if the student didn't learn, it's not always because they are a "bad student" whatever that is..
It doesn't really weed out the lazies, just people who don't learn well that way or didn't get it for whatever reason. Everyone's different and some instructors don't seem to get that if the student didn't learn, it's not always because they are a "bad student" whatever that is..
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That's good then. My calc tests were 2 sheets of paper, 4 problems, 70 minutes. If you botched a single stage of the differentiation or something you were ****ed. I ****ING HATED THAT ****. I ain't no Good Will Hunting.
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This is pretty entertaining... But a little sad too.
It doesn't really weed out the lazies, just people who don't learn well that way or didn't get it for whatever reason. Everyone's different and some instructors don't seem to get that if the student didn't learn, it's not always because they are a "bad student" whatever that is..
It doesn't really weed out the lazies, just people who don't learn well that way or didn't get it for whatever reason. Everyone's different and some instructors don't seem to get that if the student didn't learn, it's not always because they are a "bad student" whatever that is..
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Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
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Who's your math teacher? I just graduated from there in '09.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
Thats what I assumed. But I guess I won't "really" know until Tuesday.
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Did you know this "renown" math department was almost shut down because they lost something around 12 million dollars, and the day before they were going to fire all of their math professors it "magically" reappeared in the account?
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It's a pretty straight forward problem. Now, if it was to find the integral of f(x)=0, then that might stump some biz calc students, since it's c.
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Who's your math teacher? I just graduated from there in '09.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
Pertaining to your question though, if the function is f(x) = 0, then f'(x) = 0. Unless this is a trick question, it's not a curveball. The derivative is the rate of change (in y in terms of x, thus dy/dx) at that exact point in the function. However, if f(x) = 0, then you have a straight horizontal line, because no matter what value you put in for x, the end result is 0. Therefore, you will have no change in the values of y, as you move along x. Which, results in 0 as your derivative. This is the same for f(x) = 1, or 2, or 3 any constant.
Went through 4 semesters of Calculus (1, 2, 3, DiffEq) and I'll never forget how to differentiate or integrate
.
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He teaches at a bunch of different schools. I think he only teaches Business Calc and Diff. Eq. at CPP.
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http://www.wolframalpha.com/input/?i...e+f%28x%29%3D0
very useful website (I work there). Use it to check any of your calculus answers!
very useful website (I work there). Use it to check any of your calculus answers!