Nice Rack
10-11-2005, 08:02 AM
#211
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Car Info: The Thundercougarfalconbird
Originally Posted by socalwrxgirl
Time
To figure how long it is going to take to reach your destination you will need to know how fast you will be traveling and how far you are going. 60 (minutes) times D (distance) divided by S (speed) equals time. The formula for this is:
60 D = T
S
or
60 D ÷ S = T
If you are traveling at a speed of 15 mph and need to go 25 miles your formula will look like this.
60 x 25 ÷ 15 = T
Your time will be 100 minutes or 1 hour and 40 minutes.
To figure how long it is going to take to reach your destination you will need to know how fast you will be traveling and how far you are going. 60 (minutes) times D (distance) divided by S (speed) equals time. The formula for this is:
60 D = T
S
or
60 D ÷ S = T
If you are traveling at a speed of 15 mph and need to go 25 miles your formula will look like this.
60 x 25 ÷ 15 = T
Your time will be 100 minutes or 1 hour and 40 minutes.
if displacement = x:
velocity = xdot, where xdot = dx/dt
acceleration = vdot, where vdot = dv/dt
All the above definitions are derivatives of displacement wrt time.
Try this one:
F = ma = m*xdd + c*xdot + k*x
xdd= x double dot or d^2x/dt^2 or second derivative of x wrt time.
what kind of motion does this equation describe?
This is how us engineers had to learn it...
Tim
Good book to read = Race Car Vehicle Dynamics, Milliken and Milliken
Last edited by samurai; 10-11-2005 at 08:18 AM.
10-11-2005, 08:51 AM
#213
Originally Posted by samurai
meh? The way I learned it was..
if displacement = x:
velocity = xdot, where xdot = dx/dt
acceleration = vdot, where vdot = dv/dt
All the above definitions are derivatives of displacement wrt time.
Try this one:
F = ma = m*xdd + c*xdot + k*x
xdd= x double dot or d^2x/dt^2 or second derivative of x wrt time.
what kind of motion does this equation describe?
This is how us engineers had to learn it...
Tim
Good book to read = Race Car Vehicle Dynamics, Milliken and Milliken
if displacement = x:
velocity = xdot, where xdot = dx/dt
acceleration = vdot, where vdot = dv/dt
All the above definitions are derivatives of displacement wrt time.
Try this one:
F = ma = m*xdd + c*xdot + k*x
xdd= x double dot or d^2x/dt^2 or second derivative of x wrt time.
what kind of motion does this equation describe?
This is how us engineers had to learn it...
Tim
Good book to read = Race Car Vehicle Dynamics, Milliken and Milliken
10-11-2005, 08:58 AM
#214
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Car Info: The Thundercougarfalconbird
Originally Posted by hey1
kx reminds me of spring rate. I am no ME just a mathCS, but you seemed to have formulated a vibration equation for us to figure out. hmm.. i could be wrong.
k= spring rate and
x= disp
So k*x is the force put on a spring to displace it an "x" amount.
Tim
10-11-2005, 09:53 AM
#215
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Car Info: The Thundercougarfalconbird
Originally Posted by socalwrxgirl
How 'bout some double penetration?
Originally Posted by kenji815
Fisty...
O_o... Fisty? That sounds painful..
Tim
10-11-2005, 10:09 AM
#216
VIP Member
Originally Posted by samurai
O_o... Fisty? That sounds painful..
Tim
Tim
1. fisting
the act or art of putting a fist in an *** or vigina, very popular practice among more evolved(kinky)gays. requires great care and huge amounts of lubrication
http://www.urbandictionary.com/define.php?term=fisting
Wow eddie is a freak!
10-11-2005, 10:37 AM
#221
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Join Date: Jan 2005
Location: I gotta have more cow bell!!!!
Posts: 9,198
Car Info: 05 STi
Originally Posted by sigma pi
^&^ still a n00b
Braht
Meaning-intelligent, smart, possessing applicable knowledge on subject matter
Usage-"Jew ain't to braht r'ya"
10-11-2005, 10:41 AM
#224
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Join Date: Jan 2005
Location: I gotta have more cow bell!!!!
Posts: 9,198
Car Info: 05 STi
Originally Posted by slowguy626
too much math in this thread, need more rack
