Question: Will the plane fly? (warning: nerdy)
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no it isn't its just a stupid hypothetical question with insufficient information to draw a positive conclusion.
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
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Originally Posted by psoper
no it isn't its just a stupid hypothetical question with insufficient information to draw a positive conclusion.
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
if the plane does not physicaly move, there is no air accross the wings, and no lift
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and even if it does move- the question says it moves, who's to say it will move fast enough to take off?
If it does, then it will- if it doesn't no amount of non-science in the world is going to make it fly
If it does, then it will- if it doesn't no amount of non-science in the world is going to make it fly
Originally Posted by psoper
no it isn't its just a stupid hypothetical question with insufficient information to draw a positive conclusion.
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
What if the plane moves no faster than say 5mph, it isn't going to fly anywhere....
Take the person running on a treadmill case... Set the treadmill for 5 mph (so it's moving backwards at 5 mph). Can you imagine a scenario where you're moving forward relative to stationary ground at 5 mph? Sure, it happens when you try to run 10 mph on the treadmill.
This is exactly the same as the plane, except the force on the plane is further decoupled from the wheel rotation rate since it doesn't rely on the wheels to generate the thrust force.
The plane goes ahead and accelerates and takes off. The only difference is its wheels spin at twice the normal rate.
And while we're on the subject, the idea that the plane stays stationary while the treadmill moves doesn't even make sense in light of the problem statement. If the plane wasn't moving, then neither would the treadmill. The plane needs some finite forward velocity for the treadmill to move backwards in the opposite direction.
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Originally Posted by MechEE
All the information needed to solve the problem is in the problem statement.
Now if it said that the plane accellerates in a forward direction to its take-off speed, then you would be correct, but the problem statement as given does not say anything other than "the plane moves"
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Originally Posted by EQ Tuning
I was asked this by a friend and I thought it was an interesting question.
A plane is standing on a runway that can move (some sort of band conveyer). The plane moves in one direction, while the conveyer moves in the opposite direction. This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in opposite direction).
The question is:
Will the plane take off or not?
Lets see how smart SRIC really is
A plane is standing on a runway that can move (some sort of band conveyer). The plane moves in one direction, while the conveyer moves in the opposite direction. This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in opposite direction).
The question is:
Will the plane take off or not?
Lets see how smart SRIC really is

A plane is standing on a runway. The plane moves in one direction.
The question is:
Will the plane take off or not?
You can't answer that, just like you can't answer it with all the conveyor crap thrown in, it is a question with insufficient given information.
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Originally Posted by MechEE
No offense intended. I apologize for my condescending tone. I've just argued about this plane problem too many times and I get a little fired up. 
Short answer is the plane takes off equivalently to that of the plane on a normal runway with wheels of twice the inertia.
Even in the case of a car driving on a treadmill, the car will move forward. The solution to the coordinate transformation of the problem is simply that the wheels spin at twice the normal speed. So in the case of a car, if you were sitting on the car on a treadmill, your speedo would say 30 mph, but the car would actually be moving forward at 15 mph. It's just an interesting brain teaser.

Short answer is the plane takes off equivalently to that of the plane on a normal runway with wheels of twice the inertia.
Even in the case of a car driving on a treadmill, the car will move forward. The solution to the coordinate transformation of the problem is simply that the wheels spin at twice the normal speed. So in the case of a car, if you were sitting on the car on a treadmill, your speedo would say 30 mph, but the car would actually be moving forward at 15 mph. It's just an interesting brain teaser.
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Originally Posted by Egan
The plane would take off quicker than normal just like any plane does when you hold the brakes or use JATO. But if it is completely stationary as Ed implied and at full throttle, it is going nowhere. Your example and the original question/my response are apples and oranges.
All the brake holding method does is hold the plane while the engines get to full throttle so that when the plane starts to roll, the engines are already at max. That's as opposed to rolling down the runway while the engines spool up. It's no different than dropping the clutch as 6k or power braking in an auto tranny car.
As for your edit, that is exactly true and it's the same reason planes launch into the wind on runways also.
All the brake holding method does is hold the plane while the engines get to full throttle so that when the plane starts to roll, the engines are already at max. That's as opposed to rolling down the runway while the engines spool up. It's no different than dropping the clutch as 6k or power braking in an auto tranny car.
As for your edit, that is exactly true and it's the same reason planes launch into the wind on runways also.
. I think I was trying to say the same thing as you but just used an analogy that did not add-up to yours.I guess I should have said what I was thinking without trying to compare it to something else. What I’m trying to say is that if you always remain at point zero, then there's no other miraculous force creating wind for lift. Basically, if you speed the treadmill/thrust to 1000mph or 0mph the weather around you remains the same which creates no lift.
Why don't you *****es email this to Mythbusters and wait for their real world experiment?
Last edited by Salty; Jan 22, 2006 at 04:35 PM.
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Originally Posted by Salty
Hey, you're the mechanical engineer
. I think I was trying to say the same thing as you but just used an analogy that did not add-up to yours.
I guess I should have said what I was thinking without trying to compare it to something else. What I’m trying to say is that if you always remain at point zero, then there's no other miraculous force creating wind for lift. Basically, if you speed the treadmill/thrust to 1000mph or 0mph the weather around you remains the same which creates no lift.
Why don't you *****es email this to Mythbusters and wait for their real world experiment?
. I think I was trying to say the same thing as you but just used an analogy that did not add-up to yours.I guess I should have said what I was thinking without trying to compare it to something else. What I’m trying to say is that if you always remain at point zero, then there's no other miraculous force creating wind for lift. Basically, if you speed the treadmill/thrust to 1000mph or 0mph the weather around you remains the same which creates no lift.
Why don't you *****es email this to Mythbusters and wait for their real world experiment?
BTW, my plans are finally done. I should get quotes in the next 2-3 weeks and then I'll have that paperwork on it's way to you.
Originally Posted by psoper
Hate to tell you but you are wrong, the problem statement makes no claim to any rate of accelleration or velocity of the plane, only that it moves and the conveyor moves faster.
Now if it said that the plane accellerates in a forward direction to its take-off speed, then you would be correct, but the problem statement as given does not say anything other than "the plane moves"
Now if it said that the plane accellerates in a forward direction to its take-off speed, then you would be correct, but the problem statement as given does not say anything other than "the plane moves"
Given that statement, the plane will take off, because the force exerted on the plane from the faster moving ground beneat it is negligible compared to the large thrust force of the engine.
Here's my opinion.
As was stated, an airplane flies when it's wing generates lift due to the difference in air pressure between the top of the wing and the bottom.
Because the wing is not moving relative to the air, nothing is acting upon the wing to lift.
I guess another scenario might explain it best.
An F1 car can literally be driven upside down in a tunnel because it generates so much downforce due to the air pressure acting on its wings. However, if you introduce it to an upside down conveyor belt that moves fast enough so that the car stays in place, there will be no increased air pressure to apply downforce on its wings; much like how there is no increased air pressure on the wings to lift it.
I guess what everyone is confused about is the difference between velocity and speed (and the theory of relativity).
As was stated, an airplane flies when it's wing generates lift due to the difference in air pressure between the top of the wing and the bottom.
Because the wing is not moving relative to the air, nothing is acting upon the wing to lift.
I guess another scenario might explain it best.
An F1 car can literally be driven upside down in a tunnel because it generates so much downforce due to the air pressure acting on its wings. However, if you introduce it to an upside down conveyor belt that moves fast enough so that the car stays in place, there will be no increased air pressure to apply downforce on its wings; much like how there is no increased air pressure on the wings to lift it.
I guess what everyone is confused about is the difference between velocity and speed (and the theory of relativity).
Originally Posted by BLegacy
Here's my opinion.
As was stated, an airplane flies when it's wing generates lift due to the difference in air pressure between the top of the wing and the bottom.
Because the wing is not moving relative to the air, nothing is acting upon the wing to lift.
I guess another scenario might explain it best.
An F1 car can literally be driven upside down in a tunnel because it generates so much downforce due to the air pressure acting on its wings. However, if you introduce it to an upside down conveyor belt that moves fast enough so that the car stays in place, there will be no increased air pressure to apply downforce on its wings; much like how there is no increased air pressure on the wings to lift it.
I guess what everyone is confused about is the difference between velocity and speed (and the theory of relativity).
As was stated, an airplane flies when it's wing generates lift due to the difference in air pressure between the top of the wing and the bottom.
Because the wing is not moving relative to the air, nothing is acting upon the wing to lift.
I guess another scenario might explain it best.
An F1 car can literally be driven upside down in a tunnel because it generates so much downforce due to the air pressure acting on its wings. However, if you introduce it to an upside down conveyor belt that moves fast enough so that the car stays in place, there will be no increased air pressure to apply downforce on its wings; much like how there is no increased air pressure on the wings to lift it.
I guess what everyone is confused about is the difference between velocity and speed (and the theory of relativity).
It's a coordinate transformation trick. Let's look at the case of the F1 car driving on a conveyor. Let's fix the conveyor for a minute so it's not moving. Now drive the F1 car up to 200 mph (speedo reads 200 mph). Now start moving the conveyor belt backwards at 100 mph. How fast is the F1 car moving relative to the motionless ground? It's moving at 100 mph forward, while the conveyor is moving 100 mph backward, and the speedo still reads 200 mph. You can trace this all the way back to starting from a stop with a conveyor that matches speed. The trick is that the F1 car just has to drive twice as fast on the moving conveyor as it would on a motionless conveyor to achieve the same absolute speed.
Same goes for the plane...
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Originally Posted by MechEE
This is the common incorrect opinion that most people have. The plane does generate speed and therefore lift, because the force that the conveyor belt applies to the plane through the wheels is negligible compared to the engine thrust.
It's a coordinate transformation trick. Let's look at the case of the F1 car driving on a conveyor. Let's fix the conveyor for a minute so it's not moving. Now drive the F1 car up to 200 mph (speedo reads 200 mph). Now start moving the conveyor belt backwards at 100 mph. How fast is the F1 car moving relative to the motionless ground? It's moving at 100 mph forward, while the conveyor is moving 100 mph backward, and the speedo still reads 200 mph. You can trace this all the way back to starting from a stop with a conveyor that matches speed. The trick is that the F1 car just has to drive twice as fast on the moving conveyor as it would on a motionless conveyor to achieve the same absolute speed.
Same goes for the plane...
It's a coordinate transformation trick. Let's look at the case of the F1 car driving on a conveyor. Let's fix the conveyor for a minute so it's not moving. Now drive the F1 car up to 200 mph (speedo reads 200 mph). Now start moving the conveyor belt backwards at 100 mph. How fast is the F1 car moving relative to the motionless ground? It's moving at 100 mph forward, while the conveyor is moving 100 mph backward, and the speedo still reads 200 mph. You can trace this all the way back to starting from a stop with a conveyor that matches speed. The trick is that the F1 car just has to drive twice as fast on the moving conveyor as it would on a motionless conveyor to achieve the same absolute speed.
Same goes for the plane...
If the plane does indeed go faster than the conveyor, then, yes, at some point it will achieve enough relative speed to generate lift and thus take off.
The problem statement is no different than putting the plane on stands that hold it in place. Even with the engines at max thrust, the plane is going nowhere. If you instantly take the stands away, the plane will not take flight.
I think the confusion is coming from the measurement of velocity. You can't mix reference frames. People seem to be measuring the vehicle speed relative to the treadmill, and then the treadmill speed relative to the earth. You need to measure them both relative to a fixed inertial reference frame (the earth). That has gone without saying in my explanations.
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Originally Posted by Egan
The problem statement is no different than putting the plane on stands that hold it in place. Even with the engines at max thrust, the plane is going nowhere. If you instantly take the stands away, the plane will not take flight.


