Physics Question.....
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From: Behind you...Waiting
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this would work except you would use the wheel closest to the inside and in order for the object to go right the rear wheels would have to be ahead of the right front tire and that would be one crazy drift!
Just to clarify.....I agree that if you GRIP a right hand turn, the object will throw left (outside) We all know this...I've tried it. Proven. Done.
But if you DRIFT a right hand turn......will object react same way? Keep in mind during a drift you are sliding, rotating, AND pivoting around a turn.
But if you DRIFT a right hand turn......will object react same way? Keep in mind during a drift you are sliding, rotating, AND pivoting around a turn.
Think about it. If you brake...where does dice go? towards windshield right? Now immediately spin rear of car left.....where's dice going?
Actually it's less a matter of where dice is going.....more a matter of where rear of car is going.
Actually it's less a matter of where dice is going.....more a matter of where rear of car is going.
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From: Behind you...Waiting
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it really has to do with direction and inertia. yes when you brake they would go forward but that is because what was once traveling the same speed is now not. the car is slowed by the brakes but anything not secured will continue to go forward. much in the same way that in order to initiate drift you must hit the brakes or break traction in the rear. though you have changed direction the dice are still moving forward or what would now be the left of the car. hold the drift long enough and they will shift to the rear depending on the angle on that drift. any ways you look at it the only way to get them on the right side would be to speed the car up while already going sideways and thus going faster than the dice were traveling when you started the drift. though they will not stay there for long and will move to either the rear or the left through the turn. there is no way to get them on the right unless the car could propel itself laterally and keep a constant increase in speed through the entire drift. but this is just my opinion
Last edited by 04sleeper; Nov 7, 2007 at 06:28 AM.
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From: kaneohe bay
Car Info: 02 wrx sedan light mod
Ok so i went and drifted though a school zone on my way to work!!! it went left in a right hand turn!!! And just to be on the safe side in case my eyes were playing tricks on me... i punked a school bus driver by drifting around him while the red lights were flashing.... and wouldn't you know it... the fuzzy dice went to the outside of my left hand drift..... score.... man that bus driver didn't know what hit him!!!!! i win!!!!!
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Let's hear it for the experimental verification! And for an explanation:
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
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From: ***10 SEC CLUB*** 10.8@128mph w/clutch issues
Car Info: 04 STI--- 435awhp@Pump Gas **520awhp @ C16 Vp
Im going left---flag swings right
Look at my pic...
Let's hear it for the experimental verification! And for an explanation:
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
Now in a doughnut, will FD react same way? Think about the new Lexus commercial
where they show the New GS.
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From: MAKAKILO, HI
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According to my book on Physics, it should pop of your rear view mirror, the mirror will splinter in flight. Slice open your juggular, and you will die.
That's why you should not drift. Death.
That's why you should not drift. Death.
Let's hear it for the experimental verification! And for an explanation:
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
Assuming a right hand corner the objects (in this case fuzzy dice, hereafter referred to as the FD) instantaneous velocity vector is always tangential to the arc of it's travel. (In this case, the corner) It's centripetal acceleration vector is always radial, pointing to the center of the arc. Because the FD are suspended the accel vector acts through the suspension point 90* to the vel vector and the inertia causes the FD to point to the outside of the curve in line with the radius.
What it boils down to is that, in a steady state, the FD will always, no matter what, be swinging out and perpendicular to the road.
If you roll through the corner with no slip the FD will swing directly towards the left. When you introduce a drift the only thing that changes is the direction that the car is pointing, nothing else. The FD still point the exact same direction but the angle of the car has changed slightly. Now, if you drift through a corner with the tail out 30* the FD will still point left, but also 30* to the rear. The only way you could get the FD to point right would be to rotate the car past 90*, at which point. obviously, it would be impossible to maintain the drift because you'd have spun out.
I was about to write pretty much the exact same answer, so I will have to agree with Bushflyr on this. Where the front and rear wheels are is irrelevant to the motion of the FD. The car, whether drifting or gripping around a corner, is still going around a corner. Going around a corner = acceleration (centripetal if speed is constant). The FD want to keep going straight (via inertia/1st Law of Mechanics), but when the car deviates from the straight path, the bra strap you have the FD dangling from will 'pull' it along for the ride as Bushflyr describes. Well done, sir.
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From: Kaneohe
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steve - if it really matters, give me a call and i can explain the physics to you, or we can discuss it at the next auto-x in a few weeks.
...... or we could just figure it out by trial and error. i volunteer to drive.
...... or we could just figure it out by trial and error. i volunteer to drive.
