That's true if the question had to be true to physics...I was under the impression that this question was purely for math.


But you're probably right...

 

wtf happened to the BAIC?

 

M= monkey's weight
B= banana's weight
W= the weight
R= rope's weight
r= rope's length
b= banana's length
m= monkey's age
mm= mother's age

mm= (1/2 x 3 x 1/2 x 4 x 2 x 1/3 x 3 x 1/4 ) m
= 3/2 m
mm= 30 - m
30 - m= 3/2 m
30
= 5/2 m
m= 12

mm= 30 - m
mm= 18

M= W
= mm
= 18 oz

R= 4/9 r
= 4/9 (12 m)
= 64 oz.

1/2 M + B
= 1/4(W+R)
B= 1/4(18 + 64) - 9
= 41/2 - 18/2
= 23/2 oz.
b= 1/2 B
= 1/2 x 23/ 2
= 23/ 4
= 5 3/4 in.

 

we have a winner! 5.75 inches is the correct answer, and pbchief nailed the proof.

(actually RU-X had the right answer way earlier, but he cheated....)

 

hey! is it really cheating? i was just using the internet for it's 2nd purpose. and how do u know that proof isn't riped off the net? (i'm not say pbchief didn't do it, so don't shoot me =D) but that prof looks like.... http://math.ucsd.edu/~mathclub/games..._business.html
but yeah! keep them math problems coming =D

 

Back in my day we were required to "show our work" to get credit on math problems.

I know things have changed, but I don't think that "google inquiry how long is the banana" would get you credit even nowadays

 

Lol

 

My answer is still correct

 

is pr0n the first purpose?

http://www.albinoblacksheep.com/flash/internet4porn

 

Only if you assume a frictionless fence rope interface, I did not see a pully being mentioned.

Yours is just the lazy answer, and its based on a false assumption, so you're WRONG!

Thanks for playing

 

This only works in a wind tunnel

 

Damn it...I got the part I thought was harder right and the part I thought I knew wrong...

 

There is no false assumption, regardless of how much friction is there, with there being no banana the system will be balanced.



I will tell you why the proof you claim to be correct is wrong.

You are using an equation that relates the weights of the rope and the weight in comparrison to the monkey and the banana. You can't do that. It is saying that the weight of the rope is all on one side of the fence when we know the rope is equal length on both sides.

Also one of the equations used is wrong, it states, R=4/9 (12m). He puts the correct answer of 64 oz but the equation should read R=1/3 (m)*16(oz/lb) --> R=1/3 (12)*16
Regardless of that it is irrelevant since the weight of the rope doesn't matter.

the whole problem is false from the start. Unless you answer the banana being zero inches long.


Lets take your answer, 18oz + 11.5oz +(1/2 * 64oz) = 18oz + (1/2 * 64oz)

yeah, that doesn't work, the monkey will fall to the ground.

My answer, 18oz + 0oz + (1/2 * 64oz) = 18oz + (1/2 * 640z)

oh look they equal each other and the monkey hangs there freely to be strangled while eating his banana.


Thanks for playing

 

Just because someone posts an problem on a university site and has a bunch of fractions backing up his answer doesn't make it able to defy physics.

 

Unless this rope is frictionless, nowhere does the problem state that the weight on both sides of the fence balances, one side can very easily be under more tension than the other, as long as that tension does not exceed the coefficient of friction between the rope and the fence- the rope doesn’t move.

Nothing in the problem statement defies physics, but your answer defies the problem statement- which explicitly says that the monkey is holding the banana- so to say there is no banana is not correct.

and the math is right, check your units....